# Unit 02 DIODE APPLICATION, Electronic Engineering Qs & Solutions AKTU

Prepare yourself for your Electronic engineering exams with crucial questions and answers from Unit 1: Semiconductor Diodes for AKTU students. For evaluate success, improve your knowledge of diode characteristics, rectifiers, and other topics.

```Dudes 🤔.. You want more useful details regarding this subject. Please keep in mind this as well.

Important Questions For Electronic Engineering:
*Unit-01     *Unit-02
*Unit-03    *Unit-04
*Unit-05    *Short-Q/Ans
*Question-Paper with solution 21-22 ```

Ans.

## Q2. Sketch VO, VDC for the network of Fig., and determine the peak inverse voltage of each diode.

Ans.

Peak inverse voltage of each diode = Vm = 100 V

Ans.

## Q4. Explain the function of the circuit of Fig. and draw the output waveform.

Ans. 1. During positive half cycle

## Q5. Draw the output waveform for the following circuits for the input waveforms, given in F. (a) and (b):

Ans. For Fig. (a),

During negative cycle of input :

1. Diode will be ON, capacitor starts charging with polarity as shown in Fig.

2. The diode will act as short circuit, therefore

VO =0 and VC= +10 V

During positive half cycle :

Output waveform of Fig. (b):

2. During entire negative half cycle, diode will be reverse biased. Therefore

## Q6. What is voltage multiplier using p-n junction diode ? Explain the operation of voltage doublers.

Ans.

• 1. The term “voltage multiplier” refers to a circuit that uses a rectifier circuit to produce a higher DC output voltage than AC input voltage.
• 2. The output of voltage doubler is twice the peak input voltage.
• 3. There are two types of voltage doubler circuits:

i. Half wave voltage doubler: The circuit diagram is shown in Fig.

• 1. During positive half-cycle of the input voltage, diode D1 is forward biased (ON) and diode D2 is reverse biased (OFF). Capacitor C1 charges to the peak value of secondary voltage Vm with polarity.
• 2. During negative half-cycle, diode D2 is ON while diode D1 is OFF. Capacitor C2 is charged upto a voltage i.e., the sum of peak-supply voltage and the voltage across C1.
• 3. During positive half-cycle: VC1 = Vm

ii. Full wave voltage doubler : The circuit diagram is shown in Fig.

VC1 = Vm

2. During negative half cycle, D1 is OFF and D2 is ON. Capacitor C2 is charged to peak value Vm. Thus output voltage with no load connected :

VO = VC1 + VC2                                                VO = 2Vm