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Unit 01 Introduction In Engineering Mechanics Important Questions.

Engineering Mechanics Unit 01 focuses on the subject’s introduction. The fundamental ideas of mechanics and how they apply to engineering are covered in this lesson. The unit’s Important Questions are intended to aid students in comprehending the foundational ideas of mechanics, including force, moment, equilibrium, and trusses.

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Important Questions For Engineering Mechanics:
*Unit-01     *Unit-02    
*Unit-03    *Unit-04 
*Unit-05    *Short-Q/Ans
*Question-Paper with solution 21-22 

Q1. Define free, fixed and forced vectors. 

Ans. i. Free Vector: Free vectors are vectors that can be moved anywhere in space parallel to their position as long as their magnitude, direction, and sense do not change. Free vector is shown in Fig. (a).

ii. Fixed Vector: A fixed vector is one whose starting point is fixed. Figure (b) displays a fixed vector.

iii. Forced Vector: Forced vectors are those that can be applied anywhere along their path of motion. A forced vector is depicted in Fig. (c). 

Define free, fixed and forced vectors

Q2. Two forces P andQ are inclined at an angle of 75°, magnitude of their resultant is 100 N. The angle between the resultant and the force P is 45°. Determine the magnitude ofP and Q. 

Ans. 

Two forces P andQ are inclined at an angle of 75°, magnitude of their resultant is 100 N. The angle between the resultant and the force P is 45°. Determine the magnitude ofP and Q

1. The resultant R of P and Q is given by, 

Two forces P andQ are inclined at an angle of 75°, magnitude of their resultant is 100 N. The angle between the resultant and the force P is 45°. Determine the magnitude ofP and Q

2. The inclination of R to the direction of the force P is given by, 

Two forces P andQ are inclined at an angle of 75°, magnitude of their resultant is 100 N. The angle between the resultant and the force P is 45°. Determine the magnitude ofP and Q

3 Putting value of P from eq. (1.4.2) in eq. (1.4.1), we get

Two forces P andQ are inclined at an angle of 75°, magnitude of their resultant is 100 N. The angle between the resultant and the force P is 45°. Determine the magnitude ofP and Q

Q3. What are the basic laws of mechanics ? 

Ans. Following are the basic laws of mechanics: 

i. Newton’s First Law of Motion: Every body remains in a condition of rest or uniform motion along a straight line, according to this theory, unless it is forced to alter its state by an external force operating on it.

ii. Newton’s Second Law of Motion: It asserts that the rate of change of momentum in the direction of motion is directly proportional to the net external force applied on a body in that direction.

iii. Newton’s Third Law of Motion: It asserts that there is always an equal and opposing reaction to every action.  

iv. Gravitational Law of Attraction: According to this law, two bodies will be drawn toward one another along their connecting line by a force that is inversely proportional to the square of the distance between their centres and directly proportional to the product of their masses.

Gravitational Law of Attraction

where,                  G = Universal gravitational constant of proportionality

Q4. The force system applied to an angle bracket is shown in Fig. Determine the magnitude, direction and line of action of the resultant force.  

The force system applied to an angle bracket is shown in Fig. Determine the magnitude, direction and line of action of the resultant force.

Ans. Given: Fig.

To Find: Magnitude, direction and line of action of the resultant force. 

1. Considering the equilibrium of force system, we have 

The force system applied to an angle bracket is shown in Fig. Determine the magnitude, direction and line of action of the resultant force.
The force system applied to an angle bracket is shown in Fig. Determine the magnitude, direction and line of action of the resultant force.
The force system applied to an angle bracket is shown in Fig. Determine the magnitude, direction and line of action of the resultant force.

Resultant will act at a distance 4.36 m from point O towards B and it will lie outside the frame.

Q5. Two smooth spheres each of radius 100 mm and weight 100 N, rest in a horizontal channel having vertical walls, the distance between which is 360 mm. Find the reactions at the points of contacts A, B, C, and D shown in Fig. below. 

Two smooth spheres each of radius 100 mm and weight 100 N, rest in a horizontal channel having vertical walls

Ans. Given: r = 100 mm = 0.1 m, W 100 N, l = 360 mm = 0.36m

To Find: Reaction at A, B, C and D. 

1. From Fig., we have

Two smooth spheres each of radius 100 mm and weight 100 N, rest in a horizontal channel having vertical walls
Two smooth spheres each of radius 100 mm and weight 100 N, rest in a horizontal channel having vertical walls
Two smooth spheres each of radius 100 mm and weight 100 N, rest in a horizontal channel having vertical walls

Q6. Write down the laws of friction

Ans. Following are the laws of friction:
1. Friction operates against the surface’s desire to move in the opposite direction.

2. As long as the surface is at rest, the force applied to it equals the force of friction.

3. The normal reaction between two surfaces and the limiting frictional force have a fixed ratio. 

4. The shape and area of the surfaces in contact have no bearing on the limiting frictional force.

5. When the two surfaces are moving, the ratio of limiting friction to normal reaction is a little bit lower. 

6. The sliding speed has no effect on the friction force.

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