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UNIT 1 Fluid and Bernoulli’s Equation Important Questions with solution in Fluid Mechanics & Fluid Machines AKTU

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Important Questions For Fluid Mechanics & Fluid Machines : 
*Unit-01     *Unit-02    
*Unit-03    *Unit-04 
*Unit-05    *Short-Q/Ans
*Question-Paper with solution 21-22 

Discuss some physical properties of fluids in brief?

Answer

These are a few of the physical characteristics of fluids:

a. Density or Mass Density:

1. It can be described in terms of mass per unit volume under constant pressure and temperature. It is also known by the name specific mass. It is denoted by p and its unit is kg/m3.

Density or Mass Density

b. Weight Density:

1.It can be characterized as the mass per unit volume at standard pressure and temperature. It also goes by the name “specific weight.” It is denoted by W and its unit is N/m3.

Weight Density

c. Specific Volume:

  1. It is defined as the volume per unit mass of fluid
Specific Volume

d. Specific Gravity:

It is the ratio of the specific weight of the given fluid to the specific weight of a standard fluid.

Specific Gravity

For liquids, standard fluid is pure water at 4 °C and air is standard fluid for gases.

e. Viscosity:

1. It is described as a fluid’s characteristic that affects how resistant it is to shearing forces. Pa-s is its SI unit and poise is its CGS unit.

2. An ideal fluid has no viscosity.

3. Viscosity of fluids is due to cohesion and adhesion.


Explain the following a. Compressibility, b. Surface tension, and C. Incompressible flow.

Answer

a. Compressibility

1. Compressibility is the quality that allows fluids to alter in volume when subjected to external pressure.

2. It is the volumetric strain divided by the compressive stress, which is known as the reciprocal of the bulk modulus of elasticity.

Explain the following a. Compressibility, b. Surface tension, and C. Incompressible flow

b. Surface Tension:

1. It is described as the tensile force acting between two immiscible liquids or on the surface of a liquid in contact with a gas.

2. It is denoted by sigma (o) and its SI unit is N/m.

3.This occurs due to the force of cohesion at the free surface as shown in Fig. 1.6.1.

Surface Tension

4.Consider a liquid molecule that is in equilibrium and is surrounded by other molecules on all sides.

5.There are no liquid molecules above the surface of a liquid’s free surface to counteract the force of the molecules below it.

6.As a result, the molecule experiences a net inward force that is normal to the surface.

7. As a result, a tiny layer of molecules forms at the free surface, acting as a membrane that allows a thin, little needle to float there.

c. Incompressible Flow:

1.It is that type of flow in which the density is constant for the fluid flow.

2. Isochoric flow, which meaning in the same place or space, is another name for incompressible flow.

3. Since the temperature and pressure of liquids and gases do not change in incompressible flow, these types of flow are simple to model.


Determine the bulk modulus of elasticity and compressibility of a liquid. If the pressure of liquid is increased from 70 N/cm2 to 130 N/cm2. The volume of liquid decreases by 0.15 %.

Suggest the device used for the measurement of fluid flow through ducts or pipes. Explain them.   OR What are the various applications of Bernoulli’s equation ? Explain them.

Answer

Some of the simple applications of Bernoulli’s equation are as follows:

A Venturimeter:

1. A venturi metre is a tool used to gauge the flow rate of a fluid via a pipe.

2. It consists of three parts, as given below :

i. A short converging part,

ii. Throat, and

ii. Diverging part.

It works on the principle of Bernouli’s theorem.

4. As shown in Fig. 1.12.1, a venturimeter is fitted in a horizontal pipe through which a fluid is flowing.

Determine the bulk modulus of elasticity and compressibility of a liquid. If the pressure of liquid is increased from 70 N/cm2 to 130 N/cm2. The volume of liquid decreases by 0.15 %.
fluid mechani

A horizontal venturimeter with a discharge coefficient of 0.98 is being used to measure the flow rate of a liquid of density 1030 kg/m3. The pipe diameter at entry to the venturi is 75 mm and The venturi throat has an area of 1000 mm2. If the flow rate is 0.011 m3/s. Determine the height difference recorded on a U-tube manometer connecting the throat to the upstream pipe. Take the relative density of mercury to be 13.6.

A horizontal venturimeter with a discharge coefficient of 0.98 is being used to measure the flow rate of a liquid of density 1030 kg/m3. The pipe diameter at entry to the venturi is 75 mm and The venturi throat has an area of 1000 mm2. If the flow rate is 0.011 m3/s. Determine the height difference recorded on a U-tube manometer connecting the throat to the upstream pipe. Take the relative density of mercury to be 13.6.
A horizontal venturimeter with a discharge coefficient of 0.98 is being used to measure the flow rate of a liquid of density 1030 kg/m3. The pipe diameter at entry to the venturi is 75 mm and The venturi throat has an area of 1000 mm2. If the flow rate is 0.011 m3/s. Determine the height difference recorded on a U-tube manometer connecting the throat to the upstream pipe. Take the relative density of mercury to be 13.6.

Find the discharge through a trapezoidal notch which is 1 m wide at the top and 0.4 m at the bottom and is 30 cm in height. The head of water on the notch is 20 cm. Assume Cd for rectangular portion = 0.62 while for triangular portion = 0.60.

Find the discharge through a trapezoidal notch which is 1 m wide at the top and 0.4 m at the bottom and is 30 cm in height. The head of water on the notch is 20 cm. Assume Cd for rectangular portion = 0.62 while for triangular portion = 0.60.
Find the discharge through a trapezoidal notch which is 1 m wide at the top and 0.4 m at the bottom and is 30 cm in height. The head of water on the notch is 20 cm. Assume Cd for rectangular portion = 0.62 while for triangular portion = 0.60.
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